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An arrow while being shot from a bow was accelerated over a distance of 2.0 ft. If its speed at the moment it left the bow was 200 ft/sec what was the average acceleration imparted by the bow? Justify any assumptions you need to make.

Ok so I know [itex] v_{0} = 200 \frac{ft}{sec} [/itex]. Also [itex] t = \frac{1}{100} [/itex] second. So would I use the equation [itex] x = x_{0}+v_{x}_{0}t + \frac{1}{2}a_{x}t^{2} [/itex]? Or [itex] 2 = v_{x}_{0}t + \frac{1}{2}a_{x}t^{2} [/itex] or [itex] 2 = 2 + \frac{1}{2}a_{x}(\frac{1}{100})^{2} [/itex]? I dont think this makes any sense. Maybe I need to make some assumptions?

Thanks

Ok so I know [itex] v_{0} = 200 \frac{ft}{sec} [/itex]. Also [itex] t = \frac{1}{100} [/itex] second. So would I use the equation [itex] x = x_{0}+v_{x}_{0}t + \frac{1}{2}a_{x}t^{2} [/itex]? Or [itex] 2 = v_{x}_{0}t + \frac{1}{2}a_{x}t^{2} [/itex] or [itex] 2 = 2 + \frac{1}{2}a_{x}(\frac{1}{100})^{2} [/itex]? I dont think this makes any sense. Maybe I need to make some assumptions?

Thanks

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